What is the circumference x^2+y^2-6x+2y-1=0 ?

The circumference x^2+y^2-6x+2y-1=0 is C=2sqrt(11)pi

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circumference x^2+y^2-6x+2y-1=0

circumference

x^{2} + y^{2} - 6 x + 2 y - 1 = 0

C = 211 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 6 x + 2 y - 1 = 0 : r = 11

C = 211 π

x^{2} + y^{2} = - 2 x

(x - 4)^{2} + (y + 4)^{2} = 36

(x - 7)^{2} + (y - 3)^{2} = 9

2 x^{2} + 2 y^{2} - 4 x + 8 y - 22 = 0

x^{2} + y^{2} - 0 x - 4 y - 64 = 0

What is the circumference x^2+y^2-6x+2y-1=0 ?
The circumference x^2+y^2-6x+2y-1=0 is C=2sqrt(11)pi