What is the circumference x^2+y^2-0x-4y-64=0 ?

The circumference x^2+y^2-0x-4y-64=0 is C=4sqrt(17)pi

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circumference x^2+y^2-0x-4y-64=0

circumference

x^{2} + y^{2} - 0 x - 4 y - 64 = 0

C = 417 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} - 0 x - 4 y - 64 = 0 : r = 217

C = 2 π 217

Refine

C = 417 π

(x + 2)^{2} + (y + 5)^{2} = 16

x^{2} + y^{2} - x - 6 y - 5 = 0

(x - 6)^{2} + (y + 5)^{2} = 64

x^{2} - 6 x + 2 y + y^{2} + 1 = 0

X^{2} + Y^{2} = 9

What is the circumference x^2+y^2-0x-4y-64=0 ?
The circumference x^2+y^2-0x-4y-64=0 is C=4sqrt(17)pi