What is the circumference (x-3)^2+(y-3)^2=7 ?

The circumference (x-3)^2+(y-3)^2=7 is C=2sqrt(7)pi

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circumference (x-3)^2+(y-3)^2=7

circumference

(x - 3)^{2} + (y - 3)^{2} = 7

C = 27 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 3)^{2} + (y - 3)^{2} = 7 : r = 7

C = 27 π

(x - 5)^{2} + y^{2} = 4

x^{2} + y^{2} - 8 x + 6 y + 16 = 0

(x - 4)^{2} + (y + 3)^{2} = 9

(x - 2.33)^{2} + (y - 1.5)^{2} = 17

x^{2} + y^{2} - 6 x + 2 y - 15 = 0

What is the circumference (x-3)^2+(y-3)^2=7 ?
The circumference (x-3)^2+(y-3)^2=7 is C=2sqrt(7)pi