What is the circumference (x-2.33)^2+(y-1.5)^2=17 ?

The circumference (x-2.33)^2+(y-1.5)^2=17 is C=2sqrt(17)pi

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circumference (x-2.33)^2+(y-1.5)^2=17

circumference

(x - 2.33)^{2} + (y - 1.5)^{2} = 17

C = 217 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x - 2.33)^{2} + (y - 1.5)^{2} = 17 : r = 17

C = 217 π

x^{2} + y^{2} - 6 x + 2 y - 15 = 0

(x + 4)^{2} + (y - 1)^{2} = 25

x^{2} + y^{2} - 6 y - 7 = 0

x^{2} + y^{2} + 6 x + 4 y + 4 = 0

(x - 0.5)^{2} + (y - 3.5)^{2} = 4

What is the circumference (x-2.33)^2+(y-1.5)^2=17 ?
The circumference (x-2.33)^2+(y-1.5)^2=17 is C=2sqrt(17)pi