What is the circumference (x+4)^2+(y-1)^2=25 ?

The circumference (x+4)^2+(y-1)^2=25 is C=10pi

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circumference (x+4)^2+(y-1)^2=25

circumference

(x + 4)^{2} + (y - 1)^{2} = 25

C = 10 π

Solution steps

C = 2 π r

Find the radius

Radius given

(x + 4)^{2} + (y - 1)^{2} = 25 : r = 5

C = 2 π 5

Refine

C = 10 π

x^{2} + y^{2} - 6 y - 7 = 0

x^{2} + y^{2} + 6 x + 4 y + 4 = 0

(x - 0.5)^{2} + (y - 3.5)^{2} = 4

x^{2} + y^{2} - 2 x = 0

(x - 1)^{2} + (y - 1)^{2} = 18

What is the circumference (x+4)^2+(y-1)^2=25 ?
The circumference (x+4)^2+(y-1)^2=25 is C=10pi