What is the circumference x^2+y^2+3x+2y-5=0 ?

The circumference x^2+y^2+3x+2y-5=0 is C=sqrt(33)pi

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circumference x^2+y^2+3x+2y-5=0

circumference

x^{2} + y^{2} + 3 x + 2 y - 5 = 0

C = 33 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 3 x + 2 y - 5 = 0 : r = \frac{33}{2}

C = 2 π \frac{33}{2}

Refine

C = 33 π

(x - 6)^{2} + (y - 4)^{2} = 5^{2}

(x - 4)^{2} + (y + 2)^{2} = 49

x^{2} + y^{2} - 4 x = 0

x^{2} + y^{2} + 4 x - 2 y + 1 = 0

(x - 1)^{2} + y^{2} = 4

What is the circumference x^2+y^2+3x+2y-5=0 ?
The circumference x^2+y^2+3x+2y-5=0 is C=sqrt(33)pi