What is the circumference x^2+y^2+2x+6y-104=0 ?

The circumference x^2+y^2+2x+6y-104=0 is C=2sqrt(114)pi

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circumference x^2+y^2+2x+6y-104=0

circumference

x^{2} + y^{2} + 2 x + 6 y - 104 = 0

C = 2114 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 2 x + 6 y - 104 = 0 : r = 114

C = 2114 π

(x - \frac{1}{2})^{2} + (y - \frac{3}{2})^{2} = 1

x^{2} + y^{2} - 4 x + 6 y + 4 = 0

x^{2} + y^{2} - 6 x - 4 y + 9 = 0

c i rc l e, f in d C i rc u m f ere n ce, g i v e n r = 13

(x - 8)^{2} + (y - 8)^{2} = 16

What is the circumference x^2+y^2+2x+6y-104=0 ?
The circumference x^2+y^2+2x+6y-104=0 is C=2sqrt(114)pi