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Popular >

circumference x^2+y^2+8x-4y+4=0

Solution

circumference

x^{2} + y^{2} + 8 x - 4 y + 4 = 0

Solution

C = 8 π

Solution steps

C = 2 π r

Find the radius

Radius given

x^{2} + y^{2} + 8 x - 4 y + 4 = 0 : r = 4

C = 2 π 4

Refine

C = 8 π

Popular Examples

circumference (x+1)^2+(y+1)^2=13 circumference

(x + 1)^{2} + (y + 1)^{2} = 13

circumference (x-3)^2+(y-1)^2=4 circumference

(x - 3)^{2} + (y - 1)^{2} = 4

circumference 4x^2+4y^2+20x-8y+9=0 circumference

4 x^{2} + 4 y^{2} + 20 x - 8 y + 9 = 0

circumference x^2+y^2<= 4^2 circumference

x^{2} + y^{2} \leq 4^{2}

circumference (x-4)^2+y^2=8 circumference

(x - 4)^{2} + y^{2} = 8

Frequently Asked Questions (FAQ)

What is the circumference x^2+y^2+8x-4y+4=0 ?
The circumference x^2+y^2+8x-4y+4=0 is C=8pi