What is (x^2)/(49)+(y^2)/(24)=1 ?

The solution to (x^2)/(49)+(y^2)/(24)=1 is Ellipse with (h,k)=(0,0),a=7,b=2sqrt(6)

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(x^2)/(49)+(y^2)/(24)=1

\frac{x ^{2}}{49} + \frac{y ^{2}}{24} = 1

(h, k) = (0, 0), a = 7, b = 26

Solution steps

\frac{x ^{2}}{49} + \frac{y ^{2}}{24} = 1

Rewrite

\frac{x ^{2}}{49} + \frac{y ^{2}}{24} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{7 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 6 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 7, b = 26

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 7, b = 26

x^{(2)} + 4 y^{(2)} - 6 x + 16 y + 21 = 0

16 x^{2} + 25 y^{2} - 64 x - 336 = 0

x^{2} + 2 y^{2} - 4 y = 6

2 x^{2} + 4 y^{2} = 1

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{9} = 1

What is (x^2)/(49)+(y^2)/(24)=1 ?
The solution to (x^2)/(49)+(y^2)/(24)=1 is Ellipse with (h,k)=(0,0),a=7,b=2sqrt(6)