What is ((x^2))/9+((y^2))/4 =1 ?

The solution to ((x^2))/9+((y^2))/4 =1 is Ellipse with (h,k)=(0,0),a=3,b=2

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((x^2))/9+((y^2))/4 =1

\frac{( x ^{2} )}{9} + \frac{( y ^{2} )}{4} = 1

(h, k) = (0, 0), a = 3, b = 2

Solution steps

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 3, b = 2

x^{2} 8 + \frac{y ^{2}}{7 ^{2}} = 1

\frac{x ^{2}}{24} + \frac{y ^{2}}{49} = 1

\frac{x ^{2}}{64} + \frac{y ^{2}}{121} = 1

\frac{( ( x + 2 ) ^{2} )}{9} + \frac{( ( y - 4 ) ^{2} )}{16} = 1

\frac{( x + 1 ) ^{2}}{25} + \frac{( y - 2 ) ^{2}}{9} = 1

What is ((x^2))/9+((y^2))/4 =1 ?
The solution to ((x^2))/9+((y^2))/4 =1 is Ellipse with (h,k)=(0,0),a=3,b=2