What is ((x-2)^2)/(3^2)+((y-(-1))^2)/(2^2)=1 ?

The solution to ((x-2)^2)/(3^2)+((y-(-1))^2)/(2^2)=1 is Ellipse with (h,k)=(2,-1),a=3,b=2

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((x-2)^2)/(3^2)+((y-(-1))^2)/(2^2)=1

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

(h, k) = (2, - 1), a = 3, b = 2

Solution steps

\frac{( x - 2 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 1), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, - 1), a = 3, b = 2

16 x^{2} - 96 x + 9 y^{2} = 0

20 (x + 1)^{2} + 9 y^{2} = 180

x^{2} + 5 y^{2} = \frac{1}{5}

3 x^{2} + 12 y^{2} + 18 x - 24 y - 69 = 0

x^{2} + y^{2} = - 8 y

What is ((x-2)^2)/(3^2)+((y-(-1))^2)/(2^2)=1 ?
The solution to ((x-2)^2)/(3^2)+((y-(-1))^2)/(2^2)=1 is Ellipse with (h,k)=(2,-1),a=3,b=2