What is (x^2)/3+y^2=1 ?

The solution to (x^2)/3+y^2=1 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x^2)/3+y^2=1

\frac{x ^{2}}{3} + y^{2} = 1

(h, k) = (0, 0), a = 3, b = 1

Solution steps

\frac{x ^{2}}{3} + y^{2} = 1

Rewrite

\frac{x ^{2}}{3} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 3, b = 1

4 x^{2} + 12 y^{2} + 24 x + 48 y + 36 = 0

4 x^{2} + 36 y^{2} + 40 x - 72 y - 8 = 0

\frac{x ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

\frac{x ^{2}}{4} + 4 y^{2} = 1

9 x^{2} + 16 y^{2} - 90 x + 256 y + 1105 = 0

What is (x^2)/3+y^2=1 ?
The solution to (x^2)/3+y^2=1 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=1