What is ((x+1)^2)/(20)+((y-1)^2)/(36)=1 ?

The solution to ((x+1)^2)/(20)+((y-1)^2)/(36)=1 is Ellipse with (h,k)=(-1,1),a=2sqrt(5),b=6

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((x+1)^2)/(20)+((y-1)^2)/(36)=1

\frac{( x + 1 ) ^{2}}{20} + \frac{( y - 1 ) ^{2}}{36} = 1

(h, k) = (- 1, 1), a = 25, b = 6

Solution steps

\frac{( x + 1 ) ^{2}}{20} + \frac{( y - 1 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{20} + \frac{( y - 1 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{( 2 5 ) ^{2}} + \frac{( y - 1 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 1), a = 25, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, 1), b = 6, a = 25

\frac{( x - 2 ) ^{2}}{9} + \frac{( y + 5 ) ^{2}}{16} = 1

x^{2} + 8 y^{2} = 64

16 x^{2} + 4 y^{2} + 96 x - 16 y + 96 = 0

\frac{( x + 1 ) ^{2}}{49} + \frac{( y - 7 ) ^{2}}{1} = 1

4 (x - 3)^{2} + 2 (y + 4)^{2} = 16

What is ((x+1)^2)/(20)+((y-1)^2)/(36)=1 ?
The solution to ((x+1)^2)/(20)+((y-1)^2)/(36)=1 is Ellipse with (h,k)=(-1,1),a=2sqrt(5),b=6