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Popular >

64-25x^2-4y^2+24y>= 0

Solution

64 - 25 x^{2} - 4 y^{2} + 24 y \geq 0

Solution

(h, k) = (0, 3), a = 2, b = 5

Solution steps

64 - 25 x^{2} - 4 y^{2} + 24 y \geq 0

Rewrite

64 - 25 x^{2} - 4 y^{2} + 24 y \geq 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 3 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 3), a = 2, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 3), b = 5, a = 2

Popular Examples

25(x+2)^2+4(y-3)^2=100

25 (x + 2)^{2} + 4 (y - 3)^{2} = 100

(x+5)^2+4(y-4)^2=16

(x + 5)^{2} + 4 (y - 4)^{2} = 16

(x^2-6x)+4(y^2+2y)=-9

(x^{2} - 6 x) + 4 (y^{2} + 2 y) = - 9

((x+5)^2)/9+((y-3)^2)/(25)=1

\frac{( x + 5 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

(((x+0)^2))/(100)+(((y+0)^2))/(49)=1

\frac{( ( x + 0 ) ^{2} )}{100} + \frac{( ( y + 0 ) ^{2} )}{49} = 1

Frequently Asked Questions (FAQ)

What is 64-25x^2-4y^2+24y>= 0 ?
The solution to 64-25x^2-4y^2+24y>= 0 is Ellipse with (h,k)=(0,3),a=2,b=5