What is 11x^2+2y^2-22=0 ?

The solution to 11x^2+2y^2-22=0 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=sqrt(11)

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11x^2+2y^2-22=0

11 x^{2} + 2 y^{2} - 22 = 0

(h, k) = (0, 0), a = 2, b = 11

Solution steps

11 x^{2} + 2 y^{2} - 22 = 0

Rewrite

11 x^{2} + 2 y^{2} - 22 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 11 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 11

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 11, a = 2

\frac{( y + 3 ) ^{2}}{81} + \frac{( x - 7 ) ^{2}}{64} = 1

x^{2} + 8 y^{2} = 8

9 x^{2} + 4 y^{2} + 36 x - 8 y + 4 = 0

7 x^{2} + 2 y^{2} = 14

4 x^{2} + 25 y^{2} - 6 x + 200 y + 304 = 0

What is 11x^2+2y^2-22=0 ?
The solution to 11x^2+2y^2-22=0 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=sqrt(11)