What is the vertices 25x^2+16y^2+100x-96y-156=0 ?

The vertices 25x^2+16y^2+100x-96y-156=0 is (-2,8),(-2,-2)

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vertices 25x^2+16y^2+100x-96y-156=0

vertices

25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0

(- 2, 8), (- 2, - 2)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0 :

Ellipse with center

(h, k) = (- 2, 3), b = 5, a = 4

(- 2, 3 + 5), (- 2, 3 - 5)

Refine

(- 2, 8), (- 2, - 2)

x^{2} + 4 y^{2} - 6 x - 16 y + 21 = 0

100 x^{2} + 36 y^{2} = 225

x^{2} + y^{2} + 2 x = 3 y

\frac{x ^{2}}{49} + \frac{y ^{2}}{169} = 1

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

What is the vertices 25x^2+16y^2+100x-96y-156=0 ?
The vertices 25x^2+16y^2+100x-96y-156=0 is (-2,8),(-2,-2)