What is (x-3)^2+y^2=4 ?

The solution to (x-3)^2+y^2=4 is Circle with (a,b)=(3,0),r=2

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(x-3)^2+y^2=4

(x - 3)^{2} + y^{2} = 4

(a, b) = (3, 0), r = 2

Solution steps

(x - 3)^{2} + y^{2} = 4

Rewrite

(x - 3)^{2} + y^{2} = 4

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = 2

y = - 4 x^{2}

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

x^{2} - 2 x - 4 y + 9 = 0

4 x^{2} + 25 y^{2} = 100

x^{2} = 4 y

What is (x-3)^2+y^2=4 ?
The solution to (x-3)^2+y^2=4 is Circle with (a,b)=(3,0),r=2