What is the foci 2205=180x^2+196y^2 ?

The foci 2205=180x^2+196y^2 is (1,0),(-1,0)

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foci 2205=180x^2+196y^2

foci

2205 = 180 x^{2} + 196 y^{2}

(1, 0), (- 1, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

2205 = 180 x^{2} + 196 y^{2} :

Ellipse with center

(h, k) = (0, 0), a = \frac{7}{2}, b = \frac{3 5}{2}

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (\frac{7}{2})^{2} - (\frac{3 5}{2})^{2} : 1

(0 + 1, 0), (0 - 1, 0)

Refine

(1, 0), (- 1, 0)

\frac{x ^{2}}{0.38 1 ^{2}} + \frac{y ^{2}}{0.372 8 ^{2}} = 1

25 x^{2} + 9 y^{2} + 150 x = 0

4 x^{2} + y^{2} - 4 y = 0

\frac{( x + 3 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{16} = 1

\frac{( x - 6 ) ^{2}}{36} + \frac{( y + 4 ) ^{2}}{16} = 1

What is the foci 2205=180x^2+196y^2 ?
The foci 2205=180x^2+196y^2 is (1,0),(-1,0)