What is the foci ((x-11)^2)/(14)+((y-13)^2)/(81)=1 ?

The foci ((x-11)^2)/(14)+((y-13)^2)/(81)=1 is (11,13+sqrt(67)),(11,13-sqrt(67))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci ((x-11)^2)/(14)+((y-13)^2)/(81)=1

foci

\frac{( x - 11 ) ^{2}}{14} + \frac{( y - 13 ) ^{2}}{81} = 1

(11, 13 + 67), (11, 13 - 67)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{( x - 11 ) ^{2}}{14} + \frac{( y - 13 ) ^{2}}{81} = 1 :

Ellipse with center

(h, k) = (11, 13), b = 9, a = 14

(11, 13 + c), (11, 13 - c)

Compute

c :

c = 9^{2} - 14^{2} : 67

(11, 13 + 67), (11, 13 - 67)

25 x^{2} + 4 y^{2} + 50 x - 16 y = 59

3 x^{2} + 7 y^{2} - 21 = 0

9 x^{2} + 6 y^{2} + 36 y = 0

\frac{( x - 1 ) ^{2}}{12} + \frac{y ^{2}}{8} = 100

\frac{x ^{2}}{64} + \frac{y ^{2}}{81} = 1

What is the foci ((x-11)^2)/(14)+((y-13)^2)/(81)=1 ?
The foci ((x-11)^2)/(14)+((y-13)^2)/(81)=1 is (11,13+sqrt(67)),(11,13-sqrt(67))