What is the foci 36x^2+288x+64y^2-256y=1472 ?

The foci 36x^2+288x+64y^2-256y=1472 is (-4+2sqrt(7),2),(-4-2sqrt(7),2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci 36x^2+288x+64y^2-256y=1472

foci

36 x^{2} + 288 x + 64 y^{2} - 256 y = 1472

(- 4 + 27, 2), (- 4 - 27, 2)

Solution steps

(h + c, k), (h - c, k)

Calculate ellipse properties

36 x^{2} + 288 x + 64 y^{2} - 256 y = 1472 :

Ellipse with center

(h, k) = (- 4, 2), a = 8, b = 6

(- 4 + c, 2), (- 4 - c, 2)

Compute

c :

c = 8^{2} - 6^{2} : 27

(- 4 + 27, 2), (- 4 - 27, 2)

\frac{x ^{2}}{81} + \frac{y ^{2}}{56} = 1

x^{2} - 4 x + 9 y^{2} + 54 y + 4 = 0

x^{2} + 4 x + 4 y^{2} - 8 y + 4 = 0

x^{2} + 5 y^{2} - 2 x + 10 y = - 1

(\frac{x}{8})^{2} + (\frac{y}{6})^{2} = 1

What is the foci 36x^2+288x+64y^2-256y=1472 ?
The foci 36x^2+288x+64y^2-256y=1472 is (-4+2sqrt(7),2),(-4-2sqrt(7),2)