What is the foci (x^2)/(8^2)+(y^2)/(9^2)=1 ?

The foci (x^2)/(8^2)+(y^2)/(9^2)=1 is (0,sqrt(17)),(0,-sqrt(17))

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foci (x^2)/(8^2)+(y^2)/(9^2)=1

foci

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{9 ^{2}} = 1

(0, 17), (0, - 17)

Solution steps

(h, k + c), (h, k - c)

Calculate ellipse properties

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{9 ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 9, a = 8

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 9^{2} - 8^{2} : 17

(0, 0 + 17), (0, 0 - 17)

Refine

(0, 17), (0, - 17)

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{16} = 1

27 x^{2} + 48 y^{2} - 54 x - 192 y - 213 = 0

\frac{x ^{2}}{46} + \frac{( y + 8 ) ^{2}}{26} = 1

2 x^{2} + 3 y^{2} + 4 x - 6 y - 1 = 0

\frac{x ^{2}}{15} + \frac{( y - 5 ) ^{2}}{20} = 1

What is the foci (x^2)/(8^2)+(y^2)/(9^2)=1 ?
The foci (x^2)/(8^2)+(y^2)/(9^2)=1 is (0,sqrt(17)),(0,-sqrt(17))