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Popular >

foci x= 1/8 y^2

Solution

foci

x = \frac{1}{8} y^{2}

Solution

(2, 0)

Solution steps

Rewrite

x = \frac{1}{8} y^{2}

in the standard form:

4 \cdot 2 (x - 0) = (y - 0)^{2}

(h, k) = (0, 0), p = 2

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(0, 0)

along the x-axis

(0 + p, 0)

= (0 + 2, 0)

Refine

(2, 0)

Popular Examples

x^2-4y^2-2x+16y=20

x^{2} - 4 y^{2} - 2 x + 16 y = 20

asymptotes of 9x^2-4y^2-72x=0 asymptotes

9 x^{2} - 4 y^{2} - 72 x = 0

foci y=2x^2 foci

y = 2 x^{2}

(x^2)/7+(y^2)/(16)=1

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

x^{2} = y + 2

Frequently Asked Questions (FAQ)

What is the foci x= 1/8 y^2 ?
The foci x= 1/8 y^2 is (2,0)