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Popular >

foci y=2x^2

Solution

foci

y = 2 x^{2}

Solution

(0, \frac{1}{8})

Solution steps

Rewrite

y = 2 x^{2}

in the standard form:

4 \cdot \frac{1}{8} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{8}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{8})

Refine

(0, \frac{1}{8})

Popular Examples

(x^2)/7+(y^2)/(16)=1

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

x^{2} = y + 2

directrix x^2=24y directrix

x^{2} = 24 y

2 x^{2} + 16 y = 0

radius x^2+y^2=25 radius

x^{2} + y^{2} = 25

Frequently Asked Questions (FAQ)

What is the foci y=2x^2 ?
The foci y=2x^2 is (0, 1/8)