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Popular >

2x^2+16y=0

Solution

2 x^{2} + 16 y = 0

Solution

(h, k) = (0, 0), p = - 2

Solution steps

2 x^{2} + 16 y = 0

Rewrite

2 x^{2} + 16 y = 0

in the standard form:

4 (- 2) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 2

Popular Examples

radius x^2+y^2=25 radius

x^{2} + y^{2} = 25

9x^2-54x+25y^2-200y=-256

9 x^{2} - 54 x + 25 y^{2} - 200 y = - 256

y^{2} = 2 x

vertexparabola y=x^2-24x-12 vertex parabola

y = x^{2} - 24 x - 12

foci (x^2}{16}-\frac{y^2)/9 =1 foci

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

Frequently Asked Questions (FAQ)

What is 2x^2+16y=0 ?
The solution to 2x^2+16y=0 is Parabola with (h,k)=(0,0),p=-2