What is the vertexparabola y=x^2-24x-12 ?

The vertexparabola y=x^2-24x-12 is Minimum (12,-156)

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vertexparabola y=x^2-24x-12

vertex parabola

y = x^{2} - 24 x - 12

Minimum (12, - 156)

Solution steps

y = x^{2} - 24 x - 12

Rewrite

y = x^{2} - 24 x - 12

in the standard form

4 \cdot \frac{1}{4} (y - (- 156)) = (x - 12)^{2}

Therefore parabola properties are:

(h, k) = (12, - 156), p = \frac{1}{4}

p < 0,

then the vertex is a maximum value

p > 0,

then the vertex is a minimum value

p = \frac{1}{4}

Minimum (12, - 156)

\frac{x ^{2}}{16} - \frac{y ^{2}}{9} = 1

x^{2} - 12 x + 16 y + 68 = 0

10 x^{2} + 4 y^{2} + 2 x + 16 y = 144

y^{2} = - 36 x

x^{2} = 4 y

What is the vertexparabola y=x^2-24x-12 ?
The vertexparabola y=x^2-24x-12 is Minimum (12,-156)