What is the eccentricity 9x^2+36y^2=324 ?

The eccentricity 9x^2+36y^2=324 is (sqrt(3))/2

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eccentricity 9x^2+36y^2=324

eccentricity

9 x^{2} + 36 y^{2} = 324

\frac{3}{2}

Solution steps

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

9 x^{2} + 36 y^{2} = 324 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = 3

= \frac{6 ^{2} - 3 ^{2}}{6}

\frac{6 ^{2} - 3 ^{2}}{6} = \frac{3}{2}

= \frac{3}{2}

5 x^{2} + 7 y^{2} = 35

3 x^{2} + y^{2} + 18 x - 2 y - 8 = 0

x^{2} + 4 y^{2} - 16 = 0

36 x^{2} + 9 y^{2} = 324

\frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

What is the eccentricity 9x^2+36y^2=324 ?
The eccentricity 9x^2+36y^2=324 is (sqrt(3))/2