What is the eccentricity (x^2)/(144)+(y^2)/(169)=1 ?

The eccentricity (x^2)/(144)+(y^2)/(169)=1 is 5/13

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eccentricity (x^2)/(144)+(y^2)/(169)=1

eccentricity

\frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1

\frac{5}{13}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 13, a = 12

= \frac{1 3 ^{2} - 1 2 ^{2}}{13}

\frac{1 3 ^{2} - 1 2 ^{2}}{13} = \frac{5}{13}

= \frac{5}{13}

\frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1

\frac{( x ) ^{2}}{12} + \frac{( y ) ^{2}}{16} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

9 x^{2} + 49 y^{2} = 441

\frac{x ^{2}}{324} + \frac{y ^{2}}{400} = 1

What is the eccentricity (x^2)/(144)+(y^2)/(169)=1 ?
The eccentricity (x^2)/(144)+(y^2)/(169)=1 is 5/13