What is the eccentricity ((x)^2)/(11)+((y)^2)/(16)=1 ?

The eccentricity ((x)^2)/(11)+((y)^2)/(16)=1 is (sqrt(5))/4

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eccentricity ((x)^2)/(11)+((y)^2)/(16)=1

eccentricity

\frac{( x ) ^{2}}{11} + \frac{( y ) ^{2}}{16} = 1

\frac{5}{4}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{11} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 4, a = 11

= \frac{4 ^{2} - ( 11 ) ^{2}}{4}

\frac{4 ^{2} - ( 11 ) ^{2}}{4} = \frac{5}{4}

= \frac{5}{4}

\frac{x ^{2}}{5} + \frac{y ^{2}}{4.58} = 1

3 x^{2} + 2 y^{2} - 12 x + 8 y + 19 = 0

\frac{x ^{2}}{196} + \frac{y ^{2}}{121} = 1

\frac{x ^{2}}{5} + \frac{y ^{2}}{20.98} = 1

16 x^{2} + 192 x + 576 + 25 y^{2} = 1600

What is the eccentricity ((x)^2)/(11)+((y)^2)/(16)=1 ?
The eccentricity ((x)^2)/(11)+((y)^2)/(16)=1 is (sqrt(5))/4