What is the eccentricity (x^2)/9+(y^2)/(49)=1 ?

The eccentricity (x^2)/9+(y^2)/(49)=1 is (2sqrt(10))/7

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eccentricity (x^2)/9+(y^2)/(49)=1

eccentricity

\frac{x ^{2}}{9} + \frac{y ^{2}}{49} = 1

\frac{2 10}{7}

Solution steps

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

\frac{x ^{2}}{9} + \frac{y ^{2}}{49} = 1 :

Ellipse with center

(h, k) = (0, 0), b = 7, a = 3

= \frac{7 ^{2} - 3 ^{2}}{7}

\frac{7 ^{2} - 3 ^{2}}{7} = \frac{2 10}{7}

= \frac{2 10}{7}

\frac{x ^{2}}{100} + \frac{y ^{2}}{36} = 1

3 x^{2} - 6 x + y^{2} + 4 y - 11 = 0

\frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1

\frac{x ^{2}}{16} + (y - 4)^{2} = 1

9 x^{2} + 4 y^{2} - 18 x + 8 y - 23 = 0

What is the eccentricity (x^2)/9+(y^2)/(49)=1 ?
The eccentricity (x^2)/9+(y^2)/(49)=1 is (2sqrt(10))/7