What is the axis ((x+2)^2)/(64)+((y-1)^2)/(81)=1 ?

The axis ((x+2)^2)/(64)+((y-1)^2)/(81)=1 is semi-major axis b=9, semi-minor axis a=8

Popular >

axis ((x+2)^2)/(64)+((y-1)^2)/(81)=1

axis

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

semi - major axis b = 9, semi - minor axis a = 8

Solution steps

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{8 ^{2}} + \frac{( y - 1 ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 1), a = 8, b = 9

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 1), b = 9, a = 8

(\frac{x - 3}{9})^{2} + (\frac{y + 1}{4})^{2} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{16} = 1

25 x^{2} + 4 y^{2} - 50 x + 16 y - 59 = 0

\frac{( x - 4 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{25} = 1

4 x^{2} + 24 x + 36 + 36 y^{2} - 360 y + 756 = 0

What is the axis ((x+2)^2)/(64)+((y-1)^2)/(81)=1 ?
The axis ((x+2)^2)/(64)+((y-1)^2)/(81)=1 is semi-major axis b=9, semi-minor axis a=8