What is (x^2)/4-(y^2)/5 =1 ?

The solution to (x^2)/4-(y^2)/5 =1 is Hyperbola with (h,k)=(0,0),a=2,b=sqrt(5)

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(x^2)/4-(y^2)/5 =1

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

(h, k) = (0, 0), a = 2, b = 5

Solution steps

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

Rewrite

\frac{x ^{2}}{4} - \frac{y ^{2}}{5} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 0 ) ^{2}}{( 5 ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 2, b = 5

\frac{( x - 5 ) ^{2}}{16} - \frac{( y + 7 ) ^{2}}{9} = - 1

2 x^{2} - y^{2} - 1 = 0

\frac{( x - 2 ) ^{2}}{4} - \frac{( y + 2 ) ^{2}}{5} = 1

\frac{( x - 3 ) ^{2}}{49} - \frac{( y + 5 ) ^{2}}{25} = 1

\frac{( x - 8 ) ^{2}}{9} - \frac{( y + 3 ) ^{2}}{16} = 1

What is (x^2)/4-(y^2)/5 =1 ?
The solution to (x^2)/4-(y^2)/5 =1 is Hyperbola with (h,k)=(0,0),a=2,b=sqrt(5)