What is (4(y-1)^2)/9-(4(x-3)^2)/(27)=1 ?

The solution to (4(y-1)^2)/9-(4(x-3)^2)/(27)=1 is Hyperbola with (h,k)=(3,1),a= 3/2 ,b=(3sqrt(3))/2

Popular >

(4(y-1)^2)/9-(4(x-3)^2)/(27)=1

\frac{4 ( y - 1 ) ^{2}}{9} - \frac{4 ( x - 3 ) ^{2}}{27} = 1

(h, k) = (3, 1), a = \frac{3}{2}, b = \frac{3 3}{2}

Solution steps

\frac{4 ( y - 1 ) ^{2}}{9} - \frac{4 ( x - 3 ) ^{2}}{27} = 1

Rewrite

\frac{4 ( y - 1 ) ^{2}}{9} - \frac{4 ( x - 3 ) ^{2}}{27} = 1

in the form of a standard hyperbola equation

\frac{( y - 1 ) ^{2}}{( \frac{3}{2} ) ^{2}} - \frac{( x - 3 ) ^{2}}{( \frac{3 3}{2} ) ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (3, 1), a = \frac{3}{2}, b = \frac{3 3}{2}

5 x^{2} - 4 y^{2} + 24 y - 56 = 0

\frac{( x + 4 ) ^{2}}{4} - (y - 1)^{2} = 1

- 9 x^{2} + y^{2} = 36

4 x^{2} - 16 x - y^{2} - 6 y + 3 = 0

(\frac{( x + 2 ) ^{2}}{16}) - (\frac{( y - 1 ) ^{2}}{9}) = 1

What is (4(y-1)^2)/9-(4(x-3)^2)/(27)=1 ?
The solution to (4(y-1)^2)/9-(4(x-3)^2)/(27)=1 is Hyperbola with (h,k)=(3,1),a= 3/2 ,b=(3sqrt(3))/2