What is ((x+4)^2)/4-(y-1)^2=1 ?

The solution to ((x+4)^2)/4-(y-1)^2=1 is Hyperbola with (h,k)=(-4,1),a=2,b=1

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((x+4)^2)/4-(y-1)^2=1

\frac{( x + 4 ) ^{2}}{4} - (y - 1)^{2} = 1

(h, k) = (- 4, 1), a = 2, b = 1

Solution steps

\frac{( x + 4 ) ^{2}}{4} - (y - 1)^{2} = 1

Rewrite

\frac{( x + 4 ) ^{2}}{4} - (y - 1)^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 4 ) ) ^{2}}{2 ^{2}} - \frac{( y - 1 ) ^{2}}{1 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 4, 1), a = 2, b = 1

- 9 x^{2} + y^{2} = 36

4 x^{2} - 16 x - y^{2} - 6 y + 3 = 0

(\frac{( x + 2 ) ^{2}}{16}) - (\frac{( y - 1 ) ^{2}}{9}) = 1

\frac{( x - 2 ) ^{2}}{9} - \frac{y ^{2}}{4} = 1

(\frac{x + 1}{25})^{2} - (\frac{y - 4}{144})^{2} = 1

What is ((x+4)^2)/4-(y-1)^2=1 ?
The solution to ((x+4)^2)/4-(y-1)^2=1 is Hyperbola with (h,k)=(-4,1),a=2,b=1