What is ((y-2)^2)/(16)-((x+1)^2)/(144)=1 ?

The solution to ((y-2)^2)/(16)-((x+1)^2)/(144)=1 is Hyperbola with (h,k)=(-1,2),a=4,b=12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y-2)^2)/(16)-((x+1)^2)/(144)=1

\frac{( y - 2 ) ^{2}}{16} - \frac{( x + 1 ) ^{2}}{144} = 1

(h, k) = (- 1, 2), a = 4, b = 12

Solution steps

\frac{( y - 2 ) ^{2}}{16} - \frac{( x + 1 ) ^{2}}{144} = 1

Rewrite

\frac{( y - 2 ) ^{2}}{16} - \frac{( x + 1 ) ^{2}}{144} = 1

in the form of a standard hyperbola equation

\frac{( y - 2 ) ^{2}}{4 ^{2}} - \frac{( x - ( - 1 ) ) ^{2}}{1 2 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 2), a = 4, b = 12

16 x^{2} - 160 x - 16 y^{2} - 128 y - 112 = 0

[f (x)]^{2} = 3 x^{2} - x + 2

\frac{x ^{2}}{5} - \frac{y ^{2}}{4} = 1

y^{2} = 4 + z^{2} - 2 z

a^{2} - b^{2} = 51

What is ((y-2)^2)/(16)-((x+1)^2)/(144)=1 ?
The solution to ((y-2)^2)/(16)-((x+1)^2)/(144)=1 is Hyperbola with (h,k)=(-1,2),a=4,b=12