What is (x^2}{16}+\frac{y^2)/9 =1 ?

The solution to (x^2}{16}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=4,b=3

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(x^2}{16}+\frac{y^2)/9 =1

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

(h, k) = (0, 0), a = 4, b = 3

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 4, b = 3

- 9 x^{2} + 4 y^{2} - 36 x - 16 y - 164 = 0

\frac{1}{4} (y + 3) = (x - 2)^{2}

x = - 2 y^{2}

x^{2} + y^{2} = 36

\frac{x ^{2}}{7} + \frac{y ^{2}}{16} = 1

What is (x^2}{16}+\frac{y^2)/9 =1 ?
The solution to (x^2}{16}+\frac{y^2)/9 =1 is Ellipse with (h,k)=(0,0),a=4,b=3