What is 16x^2-y^2+16y-128=0 ?

The solution to 16x^2-y^2+16y-128=0 is Hyperbola with (h,k)=(0,8),a=2,b=8

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16x^2-y^2+16y-128=0

16 x^{2} - y^{2} + 16 y - 128 = 0

(h, k) = (0, 8), a = 2, b = 8

Solution steps

16 x^{2} - y^{2} + 16 y - 128 = 0

Rewrite

16 x^{2} - y^{2} + 16 y - 128 = 0

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} - \frac{( y - 8 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 8), a = 2, b = 8

(\frac{y ^{2}}{4}) - (\frac{x ^{2}}{9}) = 1

\frac{( y + 1 ) ^{2}}{5 ^{2}} - \frac{( x - 1 ) ^{2}}{1 ^{2}} = 1

4 x^{2} + 4 (0)^{2} - z^{2} = 4

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 1 ) ^{2}}{16} = 1

16 x^{2} - 25 y^{2} + 256 x + 150 y + 399 = 0

What is 16x^2-y^2+16y-128=0 ?
The solution to 16x^2-y^2+16y-128=0 is Hyperbola with (h,k)=(0,8),a=2,b=8