What is ((x+1)/(36))^2-((y-4)/(64))^2=1 ?

The solution to ((x+1)/(36))^2-((y-4)/(64))^2=1 is Hyperbola with (h,k)=(-1,4),a=36,b=64

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((x+1)/(36))^2-((y-4)/(64))^2=1

(\frac{x + 1}{36})^{2} - (\frac{y - 4}{64})^{2} = 1

(h, k) = (- 1, 4), a = 36, b = 64

Solution steps

(\frac{x + 1}{36})^{2} - (\frac{y - 4}{64})^{2} = 1

Rewrite

(\frac{x + 1}{36})^{2} - (\frac{y - 4}{64})^{2} = 1

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{3 6 ^{2}} - \frac{( y - 4 ) ^{2}}{6 4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 36, b = 64

\frac{( x - 3 ) ^{2}}{36} - \frac{( y - 2 ) ^{2}}{64} = 1

4 x^{2} - 5 y^{2} - 36 y - 36 = 0

y^{2} - 1 = 16 (x^{2} - 1)

5 x^{2} - 4 y^{2} - 18 y + 9 = 0

\frac{( x + 3 ) ^{2}}{4} - \frac{( y + 1 ) ^{2}}{9} = 1

What is ((x+1)/(36))^2-((y-4)/(64))^2=1 ?
The solution to ((x+1)/(36))^2-((y-4)/(64))^2=1 is Hyperbola with (h,k)=(-1,4),a=36,b=64