What is the vertices (x^2-y^2)/(24)=1 ?

The vertices (x^2-y^2)/(24)=1 is (2sqrt(6),0),(-2sqrt(6),0)

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vertices (x^2-y^2)/(24)=1

vertices

\frac{x ^{2} - y ^{2}}{24} = 1

(26, 0), (- 26, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate Hyperbola properties

\frac{x ^{2} - y ^{2}}{24} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 26, b = 26

(0 + 26, 0), (0 - 26, 0)

Refine

(26, 0), (- 26, 0)

x^{2} + 6 x = 9 y^{2}

\frac{y ^{2}}{4 8 ^{2}} - \frac{x ^{2}}{2 0 ^{2}} = 1

x^{2} - y^{2} + 2 x + 2 y - 16 = 0

8 x^{2} - 2 y^{2} = 16

\frac{( y - 2 ) ^{2}}{25} - \frac{x ^{2}}{9} = 1

What is the vertices (x^2-y^2)/(24)=1 ?
The vertices (x^2-y^2)/(24)=1 is (2sqrt(6),0),(-2sqrt(6),0)