What is the vertices ((y-2)^2)/(17)-((x-8)^2)/(25)=1 ?

The vertices ((y-2)^2)/(17)-((x-8)^2)/(25)=1 is (8,2+sqrt(17)),(8,2-sqrt(17))

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vertices ((y-2)^2)/(17)-((x-8)^2)/(25)=1

vertices

\frac{( y - 2 ) ^{2}}{17} - \frac{( x - 8 ) ^{2}}{25} = 1

(8, 2 + 17), (8, 2 - 17)

Solution steps

(h, k + a), (h, k - a)

Calculate Hyperbola properties

\frac{( y - 2 ) ^{2}}{17} - \frac{( x - 8 ) ^{2}}{25} = 1 :

Up-down Hyperbola with

(h, k) = (8, 2), a = 17, b = 5

(8, 2 + 17), (8, 2 - 17)

\frac{( x - 3 ) ^{2}}{4} - \frac{y ^{2}}{25} = 1

\frac{y ^{2}}{16} - \frac{x ^{2}}{1} = 1

\frac{x ^{2}}{4} - y^{2} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{4} = 1

x^{2} + 5 x - y^{2} + 3 y = 1

What is the vertices ((y-2)^2)/(17)-((x-8)^2)/(25)=1 ?
The vertices ((y-2)^2)/(17)-((x-8)^2)/(25)=1 is (8,2+sqrt(17)),(8,2-sqrt(17))