What is the foci 16x^2-25y^2=400 ?

The foci 16x^2-25y^2=400 is (sqrt(41),0),(-sqrt(41),0)

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foci 16x^2-25y^2=400

foci

16 x^{2} - 25 y^{2} = 400

(41, 0), (- 41, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

16 x^{2} - 25 y^{2} = 400 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 5, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 5^{2} + 4^{2} : 41

(0 + 41, 0), (0 - 41, 0)

Refine

(41, 0), (- 41, 0)

9 y^{2} - 16 x^{2} = 144

\frac{x ^{2}}{144} - \frac{y ^{2}}{25} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

\frac{( x - 5 ) ^{2}}{16} - \frac{( y + 7 ) ^{2}}{9} = - 1

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0

What is the foci 16x^2-25y^2=400 ?
The foci 16x^2-25y^2=400 is (sqrt(41),0),(-sqrt(41),0)