What is the foci (y^2)/(25)-(x^2)/(81)=1 ?

The foci (y^2)/(25)-(x^2)/(81)=1 is (0,sqrt(106)),(0,-sqrt(106))

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foci (y^2)/(25)-(x^2)/(81)=1

foci

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

(0, 106), (0, - 106)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 5, b = 9

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 5^{2} + 9^{2} : 106

(0, 0 + 106), (0, 0 - 106)

Refine

(0, 106), (0, - 106)

\frac{( x - 5 ) ^{2}}{16} - \frac{( y + 7 ) ^{2}}{9} = - 1

18 x^{2} - 32 y^{2} - 108 y - 128 x - 254 = 0

\frac{y ^{2}}{15} - \frac{x ^{2}}{1} = 1

x^{2} - y^{2} + 7 x + 8 y = 5

- x^{2} + y^{2} = 1

What is the foci (y^2)/(25)-(x^2)/(81)=1 ?
The foci (y^2)/(25)-(x^2)/(81)=1 is (0,sqrt(106)),(0,-sqrt(106))