What is the foci-9x^2-32y=-16y^2+128 ?

The foci-9x^2-32y=-16y^2+128 is (0,6),(0,-4)

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foci-9x^2-32y=-16y^2+128

foci

- 9 x^{2} - 32 y = - 16 y^{2} + 128

(0, 6), (0, - 4)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

- 9 x^{2} - 32 y = - 16 y^{2} + 128 :

Up-down Hyperbola with

(h, k) = (0, 1), a = 3, b = 4

(0, 1 + c), (0, 1 - c)

Compute

c :

c = 3^{2} + 4^{2} : 5

(0, 1 + 5), (0, 1 - 5)

Refine

(0, 6), (0, - 4)

\frac{x ^{2}}{16} - \frac{y ^{2}}{16} = 1

16 y^{2} - x^{2} + 2 x + 64 y + 47 = 0

\frac{( x + 1 ) ^{2}}{9} - \frac{( y - 3 ) ^{2}}{16} = 1

\frac{x ^{2}}{25} - \frac{y ^{2}}{64} = 1

\frac{x ^{2}}{4} - \frac{y ^{2}}{12} = 1

What is the foci-9x^2-32y=-16y^2+128 ?
The foci-9x^2-32y=-16y^2+128 is (0,6),(0,-4)