What is the foci (x^2)/4-(y^2)/1 =1 ?

The foci (x^2)/4-(y^2)/1 =1 is (sqrt(5),0),(-sqrt(5),0)

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foci (x^2)/4-(y^2)/1 =1

foci

\frac{x ^{2}}{4} - \frac{y ^{2}}{1} = 1

(5, 0), (- 5, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{4} - \frac{y ^{2}}{1} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 1

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 1^{2} : 5

(0 + 5, 0), (0 - 5, 0)

Refine

(5, 0), (- 5, 0)

12 x^{2} - 3 y^{2} = 36

\frac{y ^{2}}{4} - \frac{x ^{2}}{36} = 1

64 y^{2} - 36 x^{2} = 2304

\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

4 y^{2} - x^{2} + 2 x + 16 y + 7 = 0

What is the foci (x^2)/4-(y^2)/1 =1 ?
The foci (x^2)/4-(y^2)/1 =1 is (sqrt(5),0),(-sqrt(5),0)