What is the foci 9x^2-y^2=36 ?

The foci 9x^2-y^2=36 is (2sqrt(10),0),(-2sqrt(10),0)

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foci 9x^2-y^2=36

foci

9 x^{2} - y^{2} = 36

(210, 0), (- 210, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

9 x^{2} - y^{2} = 36 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 2, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 2^{2} + 6^{2} : 210

(0 + 210, 0), (0 - 210, 0)

Refine

(210, 0), (- 210, 0)

\frac{( y - 2 ) ^{2}}{4} - \frac{( x + 3 ) ^{2}}{9} = 1

16 x^{2} - 20 y^{2} - 320 = 0

\frac{x ^{2}}{25} - \frac{y ^{2}}{121} = 1

5 y^{2} - 4 x^{2} - 80 = 0

y^{2} + 2 y = 4 x^{2} + 3

What is the foci 9x^2-y^2=36 ?
The foci 9x^2-y^2=36 is (2sqrt(10),0),(-2sqrt(10),0)