What is the foci 16x^2-20y^2-320=0 ?

The foci 16x^2-20y^2-320=0 is (6,0),(-6,0)

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foci 16x^2-20y^2-320=0

foci

16 x^{2} - 20 y^{2} - 320 = 0

(6, 0), (- 6, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

16 x^{2} - 20 y^{2} - 320 = 0 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 25, b = 4

(0 + c, 0), (0 - c, 0)

Compute

c :

c = (25)^{2} + 4^{2} : 6

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

\frac{x ^{2}}{25} - \frac{y ^{2}}{121} = 1

5 y^{2} - 4 x^{2} - 80 = 0

y^{2} + 2 y = 4 x^{2} + 3

9 x^{2} - 4 y^{2} - 18 x + 16 y - 43 = 0

\frac{x ^{2}}{36} - \frac{y ^{2}}{81} = 1