What is the foci (y^2)/(4^2)-(x^2)/(3^2)=1 ?

The foci (y^2)/(4^2)-(x^2)/(3^2)=1 is (0,5),(0,-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

foci (y^2)/(4^2)-(x^2)/(3^2)=1

foci

\frac{y ^{2}}{4 ^{2}} - \frac{x ^{2}}{3 ^{2}} = 1

(0, 5), (0, - 5)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

\frac{y ^{2}}{4 ^{2}} - \frac{x ^{2}}{3 ^{2}} = 1 :

Up-down Hyperbola with

(h, k) = (0, 0), a = 4, b = 3

(0, 0 + c), (0, 0 - c)

Compute

c :

c = 4^{2} + 3^{2} : 5

(0, 0 + 5), (0, 0 - 5)

Refine

(0, 5), (0, - 5)

x^{2} - \frac{y ^{2}}{25} = 1

x^{2} - 9 y^{2} = 144

\frac{( x - 1 ) ^{2}}{25} - \frac{( y + 3 ) ^{2}}{9} = 1

\frac{( x - 3 ) ^{2}}{3} - \frac{( y - 2 ) ^{2}}{22} = 1

2 x^{2} - y^{2} = 4

What is the foci (y^2)/(4^2)-(x^2)/(3^2)=1 ?
The foci (y^2)/(4^2)-(x^2)/(3^2)=1 is (0,5),(0,-5)