What is the foci (x^2)/9-(y^2)/(36)=1 ?

The foci (x^2)/9-(y^2)/(36)=1 is (3sqrt(5),0),(-3sqrt(5),0)

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foci (x^2)/9-(y^2)/(36)=1

foci

\frac{x ^{2}}{9} - \frac{y ^{2}}{36} = 1

(35, 0), (- 35, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{9} - \frac{y ^{2}}{36} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 6

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 6^{2} : 35

(0 + 35, 0), (0 - 35, 0)

Refine

(35, 0), (- 35, 0)

\frac{x ^{2}}{4} - \frac{( y - 6 ) ^{2}}{140} = 1

\frac{y ^{2}}{5} - \frac{x ^{2}}{5} = 1

(x - 3)^{2} - \frac{y ^{2}}{9} = 1

\frac{1}{144} x^{2} - \frac{1}{196} y^{2} = 1

- 9 x^{2} + y^{2} = 36

What is the foci (x^2)/9-(y^2)/(36)=1 ?
The foci (x^2)/9-(y^2)/(36)=1 is (3sqrt(5),0),(-3sqrt(5),0)