What is the foci x^2-y^2+4x-2y=-2 ?

The foci x^2-y^2+4x-2y=-2 is (-2+sqrt(2),-1),(-2-sqrt(2),-1)

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foci x^2-y^2+4x-2y=-2

foci

x^{2} - y^{2} + 4 x - 2 y = - 2

(- 2 + 2, - 1), (- 2 - 2, - 1)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

x^{2} - y^{2} + 4 x - 2 y = - 2 :

Right-left Hyperbola with

(h, k) = (- 2, - 1), a = 1, b = 1

(- 2 + c, - 1), (- 2 - c, - 1)

Compute

c :

c = 1^{2} + 1^{2} : 2

(- 2 + 2, - 1), (- 2 - 2, - 1)

- \frac{( x + 1 ) ^{2}}{25} + \frac{( y + 5 ) ^{2}}{16} = 1

\frac{( x ^{2} )}{4} - 0.12 y^{2} = 1

9 y^{2} - 16 x^{2} = 81

9 x^{2} - 36 x - 4 y^{2} = 0

\frac{y ^{2}}{6} - \frac{x ^{2}}{6} = 1

What is the foci x^2-y^2+4x-2y=-2 ?
The foci x^2-y^2+4x-2y=-2 is (-2+sqrt(2),-1),(-2-sqrt(2),-1)