What is the foci 16x^2-9y^2-64x-18y+199=0 ?

The foci 16x^2-9y^2-64x-18y+199=0 is (2,4),(2,-6)

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foci 16x^2-9y^2-64x-18y+199=0

foci

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

(2, 4), (2, - 6)

Solution steps

(h, k + c), (h, k - c)

Calculate Hyperbola properties

16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0 :

Up-down Hyperbola with

(h, k) = (2, - 1), a = 4, b = 3

(2, - 1 + c), (2, - 1 - c)

Compute

c :

c = 4^{2} + 3^{2} : 5

(2, - 1 + 5), (2, - 1 - 5)

Refine

(2, 4), (2, - 6)

\frac{x ^{2}}{144} - \frac{y ^{2}}{81} = 1

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

- 9 x^{2} + y^{2} + 54 x - 117 = 0

\frac{( y ^{2} )}{27} - \frac{( x ^{2} )}{9} = 1

64 x^{2} - 100 y^{2} = 6400

What is the foci 16x^2-9y^2-64x-18y+199=0 ?
The foci 16x^2-9y^2-64x-18y+199=0 is (2,4),(2,-6)