What is the foci (x^2)/(144)-(y^2)/(81)=1 ?

The foci (x^2)/(144)-(y^2)/(81)=1 is (15,0),(-15,0)

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foci (x^2)/(144)-(y^2)/(81)=1

foci

\frac{x ^{2}}{144} - \frac{y ^{2}}{81} = 1

(15, 0), (- 15, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

\frac{x ^{2}}{144} - \frac{y ^{2}}{81} = 1 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 12, b = 9

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 1 2^{2} + 9^{2} : 15

(0 + 15, 0), (0 - 15, 0)

Refine

(15, 0), (- 15, 0)

\frac{y ^{2}}{25} - \frac{x ^{2}}{49} = 1

- 9 x^{2} + y^{2} + 54 x - 117 = 0

\frac{( y ^{2} )}{27} - \frac{( x ^{2} )}{9} = 1

64 x^{2} - 100 y^{2} = 6400

(\frac{( x ^{2} )}{27}) - \frac{( ( y - 3 ) ^{2} )}{36} = 1

What is the foci (x^2)/(144)-(y^2)/(81)=1 ?
The foci (x^2)/(144)-(y^2)/(81)=1 is (15,0),(-15,0)